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15.【答案】(除[文]标注外,每空2分)[章](1)2C203+[来]4N2CO2+3M[自]N2CO4+4CO[知]2(2)fe2O3[嘛](1分)、H12S[答]iO3(1分)(3[案])2C02+2H=[网]Cr207+H2O[文],加入硫酸平衡正向[章]移动,CO2转化为[来]Cx202(4)a[自]de(5)5.6([知]6)中和硫酸提高p[嘛]H、促进C水解沉淀[答](7)4C02+3[案]HCH0+4H2O[网]==4Cr(OH)[文]31+20H+3c[章]03焙烧【解析】([来]1)2Cr2O3+[自]4Na2CO3+3[知]02=4N2CnO[嘛]4+4C02(2)[答]铬矿石(主要成分是[案]C203,含FeO[网]、SO2等杂质)中[文]加入纯碱和氧气,高[章]温下,sO2和纯碱[来]反应生成硅酸钠,F[自]eO被氧化为氧化铁[知],固体1为Fe2O[嘛]3,酸化后固体2为[答]H25O3(3)2[案]C02+2H=Cr[网]202+H2O,加[文]入酸平衡正向移动生[章]成c0O7(4)重[来]铬酸钾溶解度随温度[自]变化很大,且0℃在[知]水中溶解度小;(5[嘛])为了使Cx3完全[答]沉淀[此时,c(C[案]3)≤105mol[网]·L1],根据K甲[文][Cx(OH)]=[章]c(Cr2)e(O[来]H)=6.4×10[自]3,c(OH)=4[知]×10-9ml·L[嘛]1,则c(H)=1[答]0/(4×10°)[案]mlL2=0.25[网]103mol·L',pH=5.6;([文]6).中和硫酸提高[章]pH、促进Cx水解[来]沉淀(7)HCHO[自]中碳元素化合价为0[知]价,该反应在碱性环[嘛]境下进行,最终生成[答]Na2CO3、Cr[案](OH)3等,根据[网]化合价升降守恒、电[文]荷守恒以及原子守恒[章]可知其反应的离子方[来]程式为:C0+3H[自]CO+4H20=4[知]Cr(OH)31+[嘛]20H+3C03
I looked at what the second man had dropped; it was jewellery[答]. It all happened too quickly,b[案]ut I soon realized what had happened.[网] They were burglars.[文] My friend Jeremy, who was waitingfo[章]r me, quickly ran out. when hearing unusual noises. We called the police and they were there 5minutes later. I gave the police officer descripti[来]ons of the thieves and told them the names theyhad called outYou were brave for trying stop them, "said the officer: We should be able to catch themwith your informati[自]on. " Jeremy told the officer the owners of the house were on holiday and gavehim a phone number. When the officer left, I told Jeremy about the mistake with the doornumbe[知]rs. I hadn, t really been brave at all, but my mix-up had stopped the burglars getting awaywith the jewelry. Jeremy's neighbor thanked me a lot when they came back. Actually I have been
